Copyright dates updating women convict dating
Even the idea create a temporary table holding only primary key and Column b, and then apply cursor to it is slow. Would u please help me how can i faster my procedure.u have given information 9i it same for oracle8i & dev6i.please help me Thank u very much for ur kind update information is really nice and working very insert----same prolem. That means -- just using math here -- that we have 600 seconds, 12,000 queries to run, 12000/60 = 20, so we are doing 20 per second -- or each query is taking 0.05 cpu seconds to run. do anything 12,000 times and you might have a problem tho! this might be one of the rare times that a temp table can be useful.
I am think of the way without using cursor, script as below. I don't understand what's the problem.i am going to give u full overview of my problem. The software is available in different portion of the country for data entry and report generation etc. What about: create global temporary table gtt ( id int primary key, cnt int ) on commit delete rows / you'll add that ONCE, it'll become part of your schema forever....
Every now and then I see a web site that has an old copyright date.
In my mind, I always think "Look at the sucker who forgot to update his copyright year!
Today in common parlance, even among some librarians, the terms publication date and copyright date may be used interchangeably. Material may have been completed and copyrighted in one year, but not published until the next for any number of reasons including seasonal sales strategies, printing delays, you name it.
The New Year is here and time to start thinking about updates and changes to your website.
No more having to change the date manually even without a php enabled webpage.
This post explains the year to include when using the international copyright symbol on your content.
There are one column in each table, call id, to link them. --For incremental/New data----- insert into A select * from B where column_name NOT IN (select column_name from B); --For Edited Data------- cursore C_AB select * from B minus select * from A For R in C_AB loop Update A set....where ... this shows how I would approach getting the first two columns -- just add the other 2 and use merge to keep filling temp -- and then update the join: [email protected] -1 5 group by urefitem ) b 6 on (temp.urefitem = b.urefitem) 7 when matched then update set amount = b.sum_total 8 when not matched then insert (urefitem,amount) values ( b.urefitem, b.sum_total) 9 / 398 rows merged. using a cursor means you are back to "slow=very_true" you already WERE updating on a bulk basis??? But when I run the following query, it takes up 50% of CPU. tab A has these columns: id, cycle, pop tab B has these columns: id, cycle, site_id,rel_cd,groupid update tab A a set pop= (select count(*) from tab B b where b.id=and a.cycle = b.cycle and b.site_id=44 and b.rel_cd in('code1','code2','code3') and b.groupid='123') where pop is null and id in(select id from tab B); call count cpu elapsed disk query current rows ------- ------ -------- ---------- ---------- ---------- ---------- ---------- Parse 1 0.00 0.00 0 0 0 0 Execute 2 496.35 499.54 7530955 9902630 76532 11444 Fetch 0 0.00 0.00 0 0 0 0 ------- ------ -------- ---------- ---------- ---------- ---------- ---------- total 3 496.35 499.54 7530955 9902630 76532 11444 Misses in library cache during parse: 0 Optimizer goal: CHOOSE Parsing user id: 305 Rows Row Source Operation ------- --------------------------------------------------- 1 UPDATE tab A 11445 MERGE JOIN 5942 VIEW VW_NSO_1 5942 SORT UNIQUE 31227 TABLE ACCESS FULL tab B 17385 SORT JOIN 12601 TABLE ACCESS FULL tab A Now my questions are: 1. We have several such updates that creates the same problems on the server from time to time and I would appreciate some guidance to resolve this.
Using cursor is ok, but it brings with a un-toleratable speed when operating on a large table. end loop End; It's working but taking a huge time/sometimes hang the computer. [email protected] update ( select upd.purchase_no u_pno, upd.amount u_a, 2 temp.purchase_no t_pno, temp.amount t_a 3 from upd, temp 4 where upd.urefitem = temp.urefitem ) 5 set u_pno = t_pno, u_a = t_a 6 / 635 rows updated. Is this time, 10 minutes for 12000 rows tables an acceptable (expected) time? Thanks Anandhi = b.cycle and b.site_id=44 and b.rel_cd in('code1','code2','code3') and b.groupid='123' 12,000 times?
